Module 4 · Lesson
Series and Parallel Circuits
Electricity and Magnetism
Series and Parallel Circuits
Orientation
Lesson goal: analyse current, voltage, and equivalent resistance in series, parallel, and combined circuits.
Students should read the circuit structure before substituting into equations.
Series and Parallel Circuits
Core Content
Series resistors:
$$R_s = R_1 + R_2 + ...$$
Parallel resistors:
$$\frac{1}{R_p} = \frac{1}{R_1} + \frac{1}{R_2} + ...$$
Kirchhoff's laws:
$$\sum I_\text{in} = \sum I_\text{out}$$
$$\sum \Delta V_\text{loop} = 0$$
| Circuit type | Current | Voltage | Resistance |
|---|---|---|---|
| series | same through components | divides across components | adds |
| parallel | splits between branches | same across branches | reciprocal sum; lower than smallest branch |
Series and Parallel Circuits
Concept Check
-
In a series circuit, current is:
- A. the same through each component
- B. zero after the first resistor
- C. larger after each resistor
- D. unrelated to the circuit
Answer: A.
-
In a parallel circuit, voltage across each branch is:
- A. the same
- B. always zero
- C. split equally regardless of resistance
- D. impossible to measure
Answer: A.
-
An ammeter should be connected:
- A. in series
- B. in parallel only
- C. across the battery only
- D. not in a circuit
Answer: A.
Series and Parallel Circuits
Applied Practice
A 12 V source is connected to a 3 ohm resistor in series with a parallel
pair of 6 ohm and 12 ohm resistors.
-
Parallel section:
$$R_p = \left(\frac{1}{6}+\frac{1}{12}\right)^{-1}=4\ \Omega$$
-
Total resistance:
$$R_\text{eq} = 3 + 4 = 7\ \Omega$$
-
Total current:
$$I = \frac{12}{7}=1.71\ \text{A}$$
Final answer: total current is $1.71\ \text{A}$.
Series and Parallel Circuits
Deep Practice And Writing
Prompt: explain why a parallel equivalent resistance is lower than any single branch resistance.
Close
Exit Check
Use the handout maintenance prompt to collect one short piece of evidence before moving on.
Open printable handout