Lesson

Module 3 · Lesson

Ray Optics

Waves and Thermodynamics

Ray Optics

Orientation

Lesson goal: use ray diagrams and thin-lens relationships to predict image location, size, orientation, and type.

The main discipline is to make the diagram and calculation agree. A ray diagram is evidence, not decoration.

Ray Optics

Core Content

The ray model approximates light as travelling in straight-line paths through a uniform medium. Thin-lens and mirror equations are useful when the paraxial approximation is reasonable: rays stay close to the principal axis and angles are small.

Key equations:

$$\frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i}$$

$$m = \frac{h_i}{h_o} = -\frac{d_i}{d_o}$$

EvidenceMeaning
real imagerays physically converge and image can be projected on a screen
virtual imagerays appear to diverge from a point and cannot be projected
negative magnificationinverted image in the chosen convention
$\lvert m\rvert > 1$image is larger than object

Ray Optics

Concept Check

  1. In a thin-lens ray diagram, a ray through the optical centre is usually drawn:

    • A. as strongly curved
    • B. approximately straight
    • C. parallel then stopped
    • D. backwards only

    Answer: B.

  2. A real image can be:

    • A. projected onto a screen
    • B. seen only by extending imaginary rays
    • C. formed without any light rays
    • D. created only by a plane mirror

    Answer: A.

  3. If $\lvert m\rvert > 1$, the image is:

    • A. smaller
    • B. the same size
    • C. magnified
    • D. always virtual

    Answer: C.

  4. Short response: explain why sign convention must be stated before using the thin-lens equation.

Ray Optics

Applied Practice

Worked Example

An object is $0.40\ \text{m}$ from a convex lens with focal length $0.15\ \text{m}$. Find the image distance.

  1. State the equation:

    $$\frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i}$$

  2. Substitute:

    $$\frac{1}{0.15} = \frac{1}{0.40} + \frac{1}{d_i}$$

  3. Solve:

    $$6.667 = 2.500 + \frac{1}{d_i}$$

    $$d_i = 0.240\ \text{m}$$

Final answer: the image forms $0.240\ \text{m}$ on the opposite side of the lens. With this convention it is a real image.

Practice Problem

An object is $0.30\ \text{m}$ from a convex lens with focal length $0.10\ \text{m}$. Calculate image distance and magnification, then state whether your ray diagram should show a real or virtual image.

Ray Optics

Deep Practice And Writing

Prompt: evaluate whether a thin-lens model is adequate for a classroom lens experiment. Your answer must mention the paraxial approximation and one source of image error.

Strong response pattern:

  1. identify the model,
  2. state the useful assumption,
  3. identify a limitation,
  4. judge whether the model is sufficient for the given purpose.

Close

Exit Check

Use the handout maintenance prompt to collect one short piece of evidence before moving on.

Open printable handout