Module 4 · Week 36 · Lesson

Practical Circuit Applications

PH11-6, PH11-7, PH11-11

Orientation

Lesson goal: apply circuit concepts to power, energy transfer, safety devices, and household-style circuit reasoning.

This is not a lab manual yet. It is the conceptual and calculation layer that the later lab sheets should attach to.

Core Content

Electrical power is the rate of energy transfer:

$$P = VI$$

$$E = Pt$$

For resistive devices:

$$P = I^2R = \frac{V^2}{R}$$

Safety devices are designed around current, heating, and fault pathways.

Device or featurePhysics role
fusemelts when current is excessive
circuit breakeropens circuit under fault condition
earth wireprovides low-resistance fault path
insulationprevents unwanted current path
parallel household wiringkeeps appliances at supply voltage independently

Concept Check

  1. A 60 W device transfers:

    • A. 60 J every second
    • B. 60 C every second
    • C. 60 V every second
    • D. 60 ohm every second

    Answer: A.

  2. Household appliances are usually connected in parallel so that:

    • A. each receives the supply voltage
    • B. current is zero
    • C. resistance disappears
    • D. voltage is used up

    Answer: A.

  3. Excess current is dangerous because it can cause:

    • A. heating
    • B. lower energy transfer
    • C. lower resistance always
    • D. no change

    Answer: A.

Applied Practice

A heater is rated at 1200 W and operates for 15 min. Calculate the energy transferred.

  1. Convert time:

    $$15\ \text{min}=900\ \text{s}$$

  2. Use:

    $$E = Pt = 1200\times900$$

  3. Result:

    $$E = 1.08\times10^6\ \text{J}$$

Final answer: $1.08\ \text{MJ}$.

Deep Practice And Writing

Prompt: explain why a fuse must be placed in series with the appliance and how it reduces risk during excessive current.

Maintenance Loop

Retrieve $P=VI$, $E=Pt$, and one safety-device mechanism.

Student Working